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在Java中如何实现双向链表

双向链表:就是有双向指针,即双向的链域。

链结点的结构:

┌────┬────┬────────┐

│ data │ next │ previous │

└────┴────┴────────┘

双向链表不必是双端链表(持有对最后一个链结点的引用),双端链表插入时是双向的。

有两条链:一条从头到尾,一条从尾到头,删除遍历时也是双向的。

/**

* 双向链表

*/

public class DoublyLinkedList<t> {

private Link<t> head; //首结点

private Link<t> rear; //尾部指针

public DoublyLinkedList() { }

public T peekHead() {

if (head != null) {

return head.data;

}

return null;

}

public boolean isEmpty() {

return head == null;

}

public void insertFirst(T data) {// 插入 到 链头

Link<t> newLink = new Link<t>(data);

if (isEmpty()) {//为空时,第1次插入的新结点为尾结点

rear = newLink;

} else {

head.previous = newLink; //旧头结点的上结点等于新结点

}

newLink.next = head; //新结点的下结点旧头结点

head = newLink; //赋值后,头结点的下结点是旧头结点,上结点null

}

public void insertLast(T data) {//在链尾 插入

Link<t> newLink = new Link<t>(data);

if (isEmpty()) {

head = newLink;

} else {

rear.next = newLink;

}

newLink.previous = rear;

rear = newLink; //赋值后,尾结点的上结点是旧尾结点,下结点null

}

public T deleteHead() {//删除 链头

if (isEmpty()) return null;

Link<t> temp = head;

head = head.next; //变更首结点,为下一结点

if (head != null) {

head.previous = null;

} else {

rear = null;

}

return temp.data;

}

public T deleteRear() {//删除 链尾

if (isEmpty()) return null;

Link<t> temp = rear;

rear = rear.previous; //变更尾结点,为上一结点

if (rear != null) {

rear.next = null;

} else {

head = null;

}

return temp.data;

}

public T find(T t) {//从头到尾find

if (isEmpty()) {

return null;

}

Link<t> find = head;

while (find != null) {

if (!find.data.equals(t)) {

find = find.next;

} else {

break;

}

}

if (find == null) {

return null;

}

return find.data;

}

public T delete(T t) {

if (isEmpty()) {

return null;

}

Link<t> current = head;

while (!current.data.equals(t)) {

current = current.next;

if (current == null) {

return null;

}

}

if (current == head) {

head = head.next;

if (head != null) {

head.previous = null;

}

} else if (current == rear) {

rear = rear.previous;

if (rear != null) {

rear.next = null;

}

} else {

//中间的非两端的结点,要移除current

current.next.previous = current.previous;

current.previous.next = current.next;

}

return current.data;

}

public boolean insertAfter(T key, T data) {//插入在key之后, key不存在return false

if (isEmpty()) {

return false;

}

Link<t> current = head;

while (!current.data.equals(key)) {

current = current.next;

if (current == null) {

return false;

}

}

Link<t> newLink = new Link<t>(data);

if (current == rear) {

rear = newLink;

} else {

newLink.next = current.next;

current.next.previous = newLink;

}

current.next = newLink;

newLink.previous = current;

return true;

}

public void displayList4Head() {//从头开始遍历

System.out.println("List (first-->last):");

Link<t> current = head;

while (current != null) {

current.displayLink();

current = current.next;

}

}

public void displayList4Rear() {//从尾开始遍历

System.out.println("List (last-->first):");

Link<t> current = rear;

while (current != null) {

current.displayLink();

current = current.previous;

}

}

class Link<t> {//链结点

T data; //数据域

Link<t> next; //后继指针,结点 链域

Link<t> previous; //前驱指针,结点 链域

Link(T data) {

this.data = data;

}

void displayLink() {

System.out.println("the data is " + data.toString());

}

}

public static void main(String[] args) {

DoublyLinkedList<integer> list = new DoublyLinkedList<integer>();

list.insertLast(1);

list.insertFirst(2);

list.insertLast(3);

list.insertFirst(4);

list.insertLast(5);

list.displayList4Head();

Integer deleteHead = list.deleteHead();

System.out.println("deleteHead:" + deleteHead);

list.displayList4Head();

Integer deleteRear = list.deleteRear();

System.out.println("deleteRear:" + deleteRear);

list.displayList4Rear();

System.out.println("find:" + list.find(6));

System.out.println("find:" + list.find(3));

System.out.println("delete find:" + list.delete(6));

System.out.println("delete find:" + list.delete(1));

list.displayList4Head();

System.out.println("----在指定key后插入----");

list.insertAfter(2, 8);

list.insertAfter(2, 9);

list.insertAfter(9, 10);

list.displayList4Head();

}

}