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inequity词典

∵a<b<0,

∴设a=-2,b=-1,

A、∵

1
a
=-
1
2
1
b
=-1,∵-
1
2
>-1,∴
1
a
1
b
,故本选项错误;

B、∵

1
|a|
=
1
2
1
|b|
=1,
1
2
<1,∴
1
|a|
1
|b|
,故本选项错误;

C、∵

1
a-b
=
1
-2+1
=-1,
1
a
=-
1
2
,-1<-
1
2
,∴
1
a-b
1
a
,故本选项错误;

D、∵ (b+

1
a
) 2 = (-1+
1
-2
) 2 =
9
4
, (a+
1
b
) 2 = (-2+
1
-1
) 2 =9,
9
4
<9,∴ (b+
1
a
) 2 < (a+
1
b
) 2 ,故本选项正确.

故选D.